Which Is The Best Persuasive Heading For This Image?

Answers

ansver

I would say the last one is the best heading for this image.

Hope this helps!

ansver

oh this man is texting while driving and he may miss some obstacles and it is very dangerous so both put together basically

ansver

I would say that C. is the answer

Explanation:

ansver

43.3 m

Explanation:

given :

the initial velocity of the car , u = 20m/s

The reaction time is 0.5s

the distance that the car will travel during the reaction time

= initial velocity x reaction time

= 20 m/s x 0.5 s

= 10 m

Now we turn our attention to the stopping distance AFTER she reacts and steps on the brakes:

recall that one of the forms that the equations of motions can be expressed is:

v² = u² + 2as

where v = final velocity = 0 because the car comes to a stop

u = initial velocity = 20m/s

a = acceleration = -6.0 m/s² (note negative sign because it is a deceleration)

s = distance traveled (we are asked to find this)

substituting the known values into the equation:

v² = u² + 2as

0² = 20² + 2(-6.0) s

0 = 400 - 12s

1.2s = 400

s = 400/12

s = 33.33 m

Total distance travelled

= distance during reacting time + distance while decelerating

= 10 + 33.3

= 43.3 m

ansver

b. 67.2 m

Explanation:

Given:

v₀ = 32 m/s

v = 0 m/s

t = 4.2 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (0 m/s + 32 m/s) (4.2 s)

Δx = 67.2 m

ansver

Explanation:

Took the test

ansver

distractions are dangerous; don't text and drive

Explanation:

edge 2020

Have a good day! remember, you are worthy! ;)

ansver

Find the distance he/she has left.

20 * 0.5 = 10

50 - 10 = 40m left

Find the deceleration.

v² = as

20² = 2a * 40

400 = 2a * 40

400 = 80a

5 = a

5m/s²

Note that the deceleration is a smaller value than her car which means that she will be able to stop before.

Best of Luck!

ansver

options?

Explanation:

you need to give the options for an answer

ansver

The car stops after 32.58 m.

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 20 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6 m/s²

Time taken by the car to stop

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-20}{-6}\\\Rightarrow t=3.33\ s$

Total Time taken by the car to stop is 0.5+3.33 = 3.83 s

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=20\times 3.83+\frac{1}{2}\times -6\times 3.83^2\\\Rightarrow s=32.58\ m$

The car stops after 32.58 m.

Distance between car and obstacle is 50-32.58 = 17.42 m

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Which is the best persuasive heading for this image? o this man is texting while driving and may no...

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